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Electric field intensity.

Answer:- The strength of an electric field is measured by noting force experienced by a unit positive charge placed at that point.The direction of field is given by direction of motion of a unit positive charge if it were free to do so.

Gauss's law in electrostatics.

Answer:- It states that for any distribution of charges the total flux linked with a closed surface is equal to 1/ ε0 times total charge enclosed with in the surface.